CAT 2018 Inequalities Question (Medium)

Question

The smallest integer n such that n - 11n 32n - 28 0 is TITA

Accepted Answer

Step 1 Given inequality n - 11n 32n - 28 0 Step 2 Factorize the cubic expression Let s try to factorize using the remainder theorem. Substitute n 2 2 - 11 2 32 2 - 28 8 - 44 64 - 28 0 Thus, n - 2 is a factor. Now, divide the expression by n - 2 n - 11n 32n - 28 n - 2 n - 9n 14 Further factorize the

CAT 2018

Quantitative

Inequalities

Medium

The smallest integer n such that n³ - 11n² + 32n - 28 > 0 is [TITA]

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