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Year

CAT 2018

Section

Quantitative

Topic

Averages

Difficulty

Hard

Question

Slot-2

The arithmetic mean of x,yx, y and zz is 8080, and that of x,y,z,ux, y, z, u and vv is 7575, where u=(x+y)2u = \tfrac{(x+y)}{2} and v=(y+z)2v = \tfrac{(y+z)}{2}. If xzx \geq z, then the minimum possible value of xx is (TITA).

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