CAT 2020 Allegations and Mixtures Question (Medium)

Question

Two alcohol solutions, A and B, are mixed in the proportion 1 3 by volume. The volume of the mixture is then doubled by adding solution A such that the resulting mixture has 72 alcohol. If solution A has 60 alcohol, then the percentage of alcohol in solution B is

Accepted Answer

Step 1 We are given that solutions A and B are mixed in the ratio 1 3. Let the volume of A used be 1 unit and B be 3 units. So, total initial volume units. Step 2 This mixture is then doubled in volume by adding solution A. So, we add another 4 units all of which is solution A. Hence, the final mixt

CAT 2020

Quantitative

Allegations and Mixtures

Medium

Two alcohol solutions, A and B, are mixed in the proportion 1:3 by volume. The volume of the mixture is then doubled by adding solution A such that the resulting mixture has 72% alcohol. If solution A has 60% alcohol, then the percentage of alcohol in solution B is

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