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CAT 2024 Progression — Previous Year Question

Year

CAT 2024

Section

Quantitative

Topic

Progression

Difficulty

Hard

Question

Slot-3

Consider the sequence t1=1t_1 = 1, t2=−1t_2 = -1, and

tn=(n−3n−1)tn−2for n≥3.t_n = \left( \frac{n - 3}{n - 1} \right)t_{n-2} \quad \text{for } n \geq 3.

Then, the value of the sum

1t2+1t4+1t6+⋯+1t2024\frac{1}{t_2} + \frac{1}{t_4} + \frac{1}{t_6} + \cdots + \frac{1}{t_{2024}}

is:

-1023132

-1022121

-1024144

-1026169

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